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X+25X^2+50=1500
We move all terms to the left:
X+25X^2+50-(1500)=0
We add all the numbers together, and all the variables
25X^2+X-1450=0
a = 25; b = 1; c = -1450;
Δ = b2-4ac
Δ = 12-4·25·(-1450)
Δ = 145001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{145001}}{2*25}=\frac{-1-\sqrt{145001}}{50} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{145001}}{2*25}=\frac{-1+\sqrt{145001}}{50} $
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